हिंदी

Cos(tanx+1)

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प्रश्न

`cos(tan sqrt(x + 1))`

योग
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उत्तर

Let y = `cos(tan sqrt(x + 1))`

`"dy"/"dx" = "d"/"dx" cos(tan sqrt(x + 1))`

= `- sin(tan sqrt(x + 1)) "d"/"dx" (tan sqrt(x + 1))`

= `-sin(tan sqrt(x + 1))sec^2 sqrt(x + 1) * "d"/"d"(x + 1)^(1/2)`

= `-sin(tan sqrt(x + 1))sec^2 sqrt(x + 1) 1/2 (sqrt(x + 1))^((-1)/2)`

∴ `(-1)/(2sqrt(x + 1)) * sin(tan sqrt(x + 1)) * sec^2 (sqrt(x + 1))`

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अध्याय 5: Continuity And Differentiability - Exercise [पृष्ठ १०९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 5 Continuity And Differentiability
Exercise | Q 31 | पृष्ठ १०९

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