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Cos-1(sinx+cosx2),-π4<x<π4

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प्रश्न

`cos^-1 ((sinx + cosx)/sqrt(2)), (-pi)/4 < x < pi/4`

योग
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उत्तर

Let y = `cos^-1 ((sin x + cosx)/sqrt(x))`

= `cos^-1 [1/sqrt(2) sin x + 1/sqrt(2) cos x]`

= `cos^-1 [sin  pi/4 sin x + cos  pi/4 * cos x]`

= `cos^-1 [cos(pi/4 - x)]`

y = `pi/4 - x`  ......`[∵ - pi/4 < x < pi/4]`

Differentiating both sides w.r.t. x

`"dy"/"dx"` = – 1

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अध्याय 5: Continuity And Differentiability - Exercise [पृष्ठ ११०]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 5 Continuity And Differentiability
Exercise | Q 37 | पृष्ठ ११०

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