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Differentiate the function with respect to x: (5⁢𝑥)^3⁢cos⁡2⁢𝑥

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प्रश्न

Differentiate the function with respect to x:

`(5x)^(3cos 2x)`

योग
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उत्तर

Let y = `(5x)^(3cos 2x)`

Taking log on both sides, we get

log y = 3 cos 2x log (5x) = 3 cos 2x [log 5 + log x]

log y = 3 cos 2x log 5 + 3 cos 2x log x     ....(1)

Differentiating (1) with respect to x, we get

`1/y dy/dx = 3 log 5 (-sin 2x)* 2 + (3 cos 2x)/x + 3 log x (-2 sin 2x)`

= `-6 log 5 sin 2x + (3 cos 2x)/x - 6 log x sin 2x`

`dy/dx = (5x)^(3cos 2x) [(3 cos 2x)/x - 6 (log 5 + log x) sin 2x]`

= `(5x)^(3 cos 2x) [(3 cos 2x)/x - 6 log 5x sin 2x]`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.9 [पृष्ठ १९१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.9 | Q 3 | पृष्ठ १९१

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