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Differentiate the function with respect to x. 2cot(x2)

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प्रश्न

Differentiate the function with respect to x. 

`2sqrt(cot(x^2))`

योग
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उत्तर

Let, y = `2 sqrt(cot (x^2))`

On differentiating with respect to x,

`dy/dx = 2 d/dx sqrt (cot(x)^2)`

= `2* 1/2 {cot (x^2)}^(-1/2)* d/dx cot (x^2)`

= `1/(sqrtcot(x^2))* {-"cosec"^2(x^2)} d/dx (x^2)`

= `1/sqrt(cot(x^2))* {- "cosec"^2 (x^2)} (2x)`

= `(-2x  "cosec"^2 (x)^2)/(sqrtcot(x^2))`

= `(-2x)/(sin^2 x^2) xx 1/(sqrt(cosx^2)/sqrt(sinx^2))`

= `(-2x)/((sinx^2)sqrt(sinx^2) sqrt(cosx^2)`

= `(-2xsqrt2)/(sinx^2 sqrt(2  sinx^2 cosx^2))`

= `(-2sqrt(2x))/(sinx^2 sqrt(sin2x^2))`

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अध्याय 5: Continuity and Differentiability - Exercise 5.2 [पृष्ठ १६६]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.2 | Q 7 | पृष्ठ १६६

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