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If y = tan(x + y), find dddydx

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प्रश्न

If y = tan(x + y), find `("d"y)/("d"x)`

योग
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उत्तर

Given y = tan (x + y).

Differentiating both sides w.r.t. x, we have

`("d"y)/("d"x) = sec^2 (x + y) "d"/("d"x) (x + y)`

= `sec^2 (x + y) (1 + ("d"y)/("d"x))`

or `[1 - sec^2 (x + y)] ("d"y)/("d"x) = sec^2 (x + y)`

Therefore, `("d"y)/("d"x) = (sec^2(x + y))/(1 - sec^2(x + y)) = - "cosec"^2 (x + y)`

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अध्याय 5: Continuity And Differentiability - Solved Examples [पृष्ठ ९३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 5 Continuity And Differentiability
Solved Examples | Q 8 | पृष्ठ ९३

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