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प्रश्न
Differentiate `sqrt(tansqrt(x))` w.r.t. x
योग
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उत्तर
Let y = `sqrt(tansqrt(x)`.
Using chain rule, we have
`("d"y)/("d"x) = 1/(2sqrt(tansqrt(x))) * "d"/("d"x) (tan sqrt(x))`
= `1/(2sqrt(tansqrt(x))) * sec^2 sqrt(x) "d"/("d"x) (sqrt(x))`
= `1/(2sqrt(tansqrt(x))) (sec^2 sqrt(x)) (1/(2sqrt(x)))`
= `(sec^2 sqrt(x))/(4sqrt(x) sqrt(tansqrt(x))`
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