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Prove that 1 9 ! + 1 10 ! + 1 11 ! = 122 11 ! - Mathematics

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प्रश्न

Prove that

\[\frac{1}{9!} + \frac{1}{10!} + \frac{1}{11!} = \frac{122}{11!}\]
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उत्तर

\[LHS = \frac{1}{9!} + \frac{1}{10!} + \frac{1}{11!}\]
\[ = \frac{1}{9!} + \frac{1}{10 \times 9!} + \frac{1}{11 \times 10 \times 9!}\]
\[ = \frac{110 + 11 + 1}{11 \times 10 \times 9!}\]
\[ = \frac{122}{11!} = RHS \hspace{0.167em} \]
\[\text{Hence, proved} .\]

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अध्याय 16: Permutations - Exercise 16.1 [पृष्ठ ४]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.1 | Q 2 | पृष्ठ ४

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