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Find n if 2nC3:nC2 = 52:3

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प्रश्न

Find n if `""^(2"n")"C"_3: ""^"n""C"_2` = 52:3

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उत्तर

∴ `(""^(2"n")"C"_3)/(""^"n""C"_2) = 52/3`

∴ `((2"n")!)/(3!(2"n" - 3)!)÷("n"!)/(2!("n" - 2)!) = 52/3`

∴ `((2"n")!)/(3!(2"n" - 3)!) xx (2!("n" - 2)!)/("n"!) = 52/3`

`∴ ((2"n")(2"n" - 1)(2"n" - 2)(2"n" - 3)!)/(3xx2!(2"n" - 3)!) xx (2!("n" - 2)!)/("n"("n" - 1)("n" - 2)!) = 52/3`

∴ `(2"n"(2"n" - 1) xx 2("n" - 1))/3 xx 1/("n"("n" - 1)) = 52/3`

∴ `(4(2"n" - 1))/3 = 52/3`

∴ 2n – 1 = `52/3 xx 3/4`

∴ 2n – 1 = 13
∴ 2n = 14
∴ n = 7

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Permutations and Combinations - Exercise 6.6 [पृष्ठ ८९]

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बालभारती Mathematics and Statistics (Commerce) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 6 Permutations and Combinations
Exercise 6.6 | Q 2. (ii) | पृष्ठ ८९

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