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प्रश्न
If 16Cr = 16Cr + 2, find rC4.
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उत्तर
Given:
\[ \Rightarrow 2r = 14\]
\[ \Rightarrow r = 7\]
[∵\[{}^n C_r = \frac{n}{r} . {}^{n - 1} C_{r - 1}\]]
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