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Compute: L.C.M. (6!, 7!, 8!)

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प्रश्न

Compute:

 L.C.M. (6!, 7!, 8!)

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उत्तर

 LCM of (6!,7! and 8!):
 n! = n(n - 1 )!
Therefore, (6!,7! and 8!) can be rewritten as:

8! = 8 X 7 X 6 !

7!= 7 X 6!

6!= 6!

∴ LCM of  (6!,7! and 8!) = LCM  [8 x 7 x 6!, 7 x 6!] = 8 x 7 x 6 ! = 8!

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अध्याय 16: Permutations - Exercise 16.1 [पृष्ठ ४]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.1 | Q 1.3 | पृष्ठ ४

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