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If 20 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, in how many points will they intersect each other?

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प्रश्न

If 20 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, in how many points will they intersect each other?

योग
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उत्तर

Given that out of 20 lines, no two lines are parallel and no three lines are concurrent.

Therefore, number of point of intersection

= 20C2  ......[∵ For any point of intersection, we need two lines]

= `(20*19)/(2*1)`

= 190

Hence, the required number of points = 190.

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अध्याय 7: Permutations and Combinations - Exercise [पृष्ठ १२३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise | Q 17 | पृष्ठ १२३

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