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A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected from the lot.

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प्रश्न

A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected from the lot.

योग
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उत्तर

Given that bag contains 5 black and 6 red balls.

Number of ways of selecting 2 black balls out of 5 black balls = 5C2

And number of ways of selecting 3 red balls out of 6 red balls = 6C3

∴ Total number of ways of selecting 2 black and 3 red balls = 5C2 × 6C3

= `(5*4)/(2*1) xx (6*5*4)/(3*2*1)`

= 10 × 20

= 200 ways

Hence, the required ways of selecting the balls = 200.

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अध्याय 7: Permutations and Combinations - Exercise [पृष्ठ १२२]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise | Q 8 | पृष्ठ १२२

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