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A committee of 7 has to be formed from 9 boys and 4 girls. In how many ways can this be done when the committee consists of: exactly 3 girls?

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प्रश्न

A committee of 7 has to be formed from 9 boys and 4 girls. In how many ways can this be done when the committee consists of: exactly 3 girls?

योग
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उत्तर

A committee of 7 members is to be formed from 9 boys and 4 girls.

When there are 3 girls in that committee, then there will be 4 boys in that committee. Ways to choose 3 girls and 4 boys

= 4C3 x 9C4

= 4C1 x 9C4

[∵ 4C3 = 4C1]

= `4/1 xx (9 xx 8 xx 7 xx 6)/(1.2.3.4)`

= 9 x 8 x 7 = 504

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अध्याय 6: Permutations and Combinations - Miscellaneous Exercise [पृष्ठ १२२]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 6 Permutations and Combinations
Miscellaneous Exercise | Q 3. (i) | पृष्ठ १२२
आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 17 Combinations
Exercise 17.2 | Q 30.1 | पृष्ठ १७

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