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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Predict the product of reaction of aniline with bromine in non-polar solvent such as CSX2.

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प्रश्न

Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].

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उत्तर


In non-polar solvent (such as \[\ce{CS2}\]) the activating effect of -NH2 group is reduced (due to resonance) and hence, mono substitution occurs only at o- and p-positions.

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अध्याय 13: Amines - Multiple Choice Questions (Type - I) [पृष्ठ १८९]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 13 Amines
Multiple Choice Questions (Type - I) | Q 49 | पृष्ठ १८९

संबंधित प्रश्न

Arenium ion involved in the bromination of aniline is:

(i)

(ii)

(iii)

(iv)


Why is benzene diazonium chloride not stored and is used immediately after its preparation?


Why does acetylation of –NH2 group of aniline reduce its activating effect?


Why is aniline soluble in aqueous HCl?


How will you carry out the following conversions?

toluene `->` p-toluidine


How will you carry out the following conversions?

p-toluidine diazonium chloride `→` p-toluic acid


Predict the reagent or the product in the following reaction sequence.


In order to distinguish between C2H5NHz and C6H5NHz, which of the following reagents is useful?


Aniline when treated with cone. HNO3 gives


Which of the following is the most stable diazonium salt?


Consider the following compounds:

(i) p-methyl aniline

(ii) N, N-dimethylaniline

(iii) N-ethyl aniline

(iv) N-ethyl-N-methyl aniline

The compounds which do not form diazonium salt with ice-colds NaNO2 and HCl are:


Major Product In the above chemical reaction, intermediate "X" and reagent/condition "A" are:


Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0 °C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:


How will the following be converted? (Give chemical equation)

Aniline to benzene diazonium chloride.


Given below are two statements:

Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.

Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.

In the light of the above statements, choose the most appropriate answer from the options given below:


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