हिंदी

Given below are two statements: Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.

Advertisements
Advertisements

प्रश्न

Given below are two statements:

Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.

Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.

In the light of the above statements, choose the most appropriate answer from the options given below:

विकल्प

  • Both Statement I and Statement II are correct.

  • Both Statement I and Statement II are incorrect.

  • Statement I is correct but Statement II is incorrect.

  • Statement I is incorrect but Statement II is correct.

MCQ
Advertisements

उत्तर

Both Statement I and Statement II are correct.

Explanation:

Aniline and nitrous acid are reacted at a temperature range of 273-278 Kelvin (0-5 degrees Celsius) to produce benzene diazonium salt, more precisely, benzenediazonium chloride. Primary aromatic amines are transformed into diazonium salts by a process known as diazotisation. The diazonium salt is unstable and is not usually preserved since it breaks down quickly in the dry condition.

Iodine is difficult to introduce into the benzene ring; hence, iodobenzene is normally synthesised by reacting benzenediazonium salt with potassium iodide (KI).

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×