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प्रश्न
Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].
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उत्तर
In non-polar solvent (such as \[\ce{CS2}\]) the activating effect of -NH2 group is reduced (due to resonance) and hence, mono substitution occurs only at o- and p-positions.
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संबंधित प्रश्न
Illustrate the following reaction giving suitable example in each case: Diazotisation
Write equations of the following reactions:
Acetylation of aniline
Arenium ion involved in the bromination of aniline is:
(i)
(ii)
(iii)
(iv)
Why is benzene diazonium chloride not stored and is used immediately after its preparation?
How will you carry out the following conversions?
toluene `->` p-toluidine
How will you carry out the following conversions?
p-toluidine diazonium chloride `→` p-toluic acid
Match the compounds given in Column I with the items given in Column II.
| Column I | Column II | ||
| (i) | Benzene sulphonyl chloride | (a) | Zwitter ion |
| (ii) | Sulphanilic acid | (b) | Hinsberg reagent |
| (iii) | Alkyl diazonium salts | (c) | Dyes |
| (iv) | Aryl diazonium salts | (d) | Conversion to alcohols |
Predict the reagent or the product in the following reaction sequence.
Which of the following statement about primary amines is false?
Which of the following is true characteristic feature of aniline?
Which of the following is the most stable diazonium salt?
Benzene diazonium chloride is a ______.
Major Product In the above chemical reaction, intermediate "X" and reagent/condition "A" are:
Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0 °C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:
Identify A and B for the following reaction:
What are polymers?
How will the following be converted? (Give chemical equation)
Aniline to benzene diazonium chloride.
Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below:
