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प्रश्न
Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].
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उत्तर
In non-polar solvent (such as \[\ce{CS2}\]) the activating effect of -NH2 group is reduced (due to resonance) and hence, mono substitution occurs only at o- and p-positions.
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संबंधित प्रश्न
Write equations of the following reactions:
Acetylation of aniline
Arenium ion involved in the bromination of aniline is:
(i)
(ii)
(iii)
(iv)
Why is benzene diazonium chloride not stored and is used immediately after its preparation?
Why does acetylation of –NH2 group of aniline reduce its activating effect?
Why is aniline soluble in aqueous HCl?
How will you carry out the following conversions?
toluene `->` p-toluidine
How will you carry out the following conversions?
p-toluidine diazonium chloride `→` p-toluic acid
A colourless substance ‘A’ \[\ce{(C6H7N)}\] is sparingly soluble in water and gives a water soluble compound ‘B’ on treating with mineral acid. On reacting with \[\ce{CHCl3}\] and alcoholic potash ‘A’ produces an obnoxious smell due to the formation of compound ‘C’. Reaction of ‘A’ with benzenesulphonyl chloride gives compound ‘D’ which is soluble in alkali. With \[\ce{NaNO2}\] and \[\ce{HCl}\], ‘A’ forms compound ‘E’ which reacts with phenol in alkaline medium to give an orange dye ‘F’. Identify compounds ‘A’ to ‘F’.
Predict the reagent or the product in the following reaction sequence.
Which of the following statement about primary amines is false?
Aniline when treated with cone. HNO3 gives
Benzene diazonium chloride is a ______.
Consider the following compounds:
(i) p-methyl aniline
(ii) N, N-dimethylaniline
(iii) N-ethyl aniline
(iv) N-ethyl-N-methyl aniline
The compounds which do not form diazonium salt with ice-colds NaNO2 and HCl are:
How will the following be converted? (Give chemical equation)
Aniline to benzene diazonium chloride.
Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below:
