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प्रश्न
Arenium ion involved in the bromination of aniline is:
(i)
(ii)
(iii)
(iv)
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उत्तर
(i)
(ii)
(iii)
Explanation:
Arenium ion involved in the bromination of aniline are as follows:
(i)
(ii)
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संबंधित प्रश्न
Illustrate the following reaction giving suitable example in each case: Diazotisation
Write equations of the following reactions:
Acetylation of aniline
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Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].
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p-toluidine diazonium chloride `→` p-toluic acid
A colourless substance ‘A’ \[\ce{(C6H7N)}\] is sparingly soluble in water and gives a water soluble compound ‘B’ on treating with mineral acid. On reacting with \[\ce{CHCl3}\] and alcoholic potash ‘A’ produces an obnoxious smell due to the formation of compound ‘C’. Reaction of ‘A’ with benzenesulphonyl chloride gives compound ‘D’ which is soluble in alkali. With \[\ce{NaNO2}\] and \[\ce{HCl}\], ‘A’ forms compound ‘E’ which reacts with phenol in alkaline medium to give an orange dye ‘F’. Identify compounds ‘A’ to ‘F’.
Predict the reagent or the product in the following reaction sequence.
Which of the following statement about primary amines is false?
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Benzene diazonium chloride is a ______.
Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0 °C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:
Identify A and B for the following reaction:
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Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below:
