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Why does acetylation of –NH2 group of aniline reduce its activating effect? - Chemistry

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प्रश्न

Why does acetylation of –NH2 group of aniline reduce its activating effect?

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उत्तर

Direct nitration of aniline is not possible on account of oxidation of –NH2 group. However, nitration can be carried after protecting the –NH2 group by acetylation to give acetanilide which is then nitrated and finally hydrolysed to give o- and p-nitroanilines.

The acetyl group being electron-withdrawing attracts the lone pair of electrons of the N-atom towards carbonyl group.

As a result, the activating effect –NH2 group is reduced i.e., the lone pair of electrons on nitrogen is less available for donation to benzene ring by resonance. Therefore, activating effect of –NHCOCH3 group is less than that of –NH2 group.

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अध्याय 13: Amines - Multiple Choice Questions (Type - I) [पृष्ठ १८९]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 13 Amines
Multiple Choice Questions (Type - I) | Q 45 | पृष्ठ १८९

संबंधित प्रश्न

Illustrate the following reaction giving suitable example in each case: Diazotisation

 


Write equations of the following reactions:
Acetylation of aniline


Arenium ion involved in the bromination of aniline is:

(i)

(ii)

(iii)

(iv)


Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].


How will you carry out the following conversions?

p-toluidine diazonium chloride `→` p-toluic acid


Match the compounds given in Column I with the items given in Column II.

  Column I   Column II
(i) Benzene sulphonyl chloride (a) Zwitter ion
(ii) Sulphanilic acid (b) Hinsberg reagent
(iii) Alkyl diazonium salts (c) Dyes
(iv) Aryl diazonium salts (d) Conversion to alcohols

A colourless substance ‘A’ \[\ce{(C6H7N)}\] is sparingly soluble in water and gives a water soluble compound ‘B’ on treating with mineral acid. On reacting with \[\ce{CHCl3}\] and alcoholic potash ‘A’ produces an obnoxious smell due to the formation of compound ‘C’. Reaction of ‘A’ with benzenesulphonyl chloride gives compound ‘D’ which is soluble in alkali. With \[\ce{NaNO2}\] and \[\ce{HCl}\], ‘A’ forms compound ‘E’ which reacts with phenol in alkaline medium to give an orange dye ‘F’. Identify compounds ‘A’ to ‘F’.


Predict the reagent or the product in the following reaction sequence.


Which of the following statement about primary amines is false?


In order to distinguish between C2H5NHz and C6H5NHz, which of the following reagents is useful?


Which of the following is true characteristic feature of aniline?


Benzene diazonium chloride is a ______.


Consider the following compounds:

(i) p-methyl aniline

(ii) N, N-dimethylaniline

(iii) N-ethyl aniline

(iv) N-ethyl-N-methyl aniline

The compounds which do not form diazonium salt with ice-colds NaNO2 and HCl are:


Major Product In the above chemical reaction, intermediate "X" and reagent/condition "A" are:


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