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प्रश्न
Match the compounds given in Column I with the items given in Column II.
| Column I | Column II | ||
| (i) | Benzene sulphonyl chloride | (a) | Zwitter ion |
| (ii) | Sulphanilic acid | (b) | Hinsberg reagent |
| (iii) | Alkyl diazonium salts | (c) | Dyes |
| (iv) | Aryl diazonium salts | (d) | Conversion to alcohols |
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उत्तर
| Column I | Column II | ||
| (i) | Benzene sulphonyl chloride | (b) |
Hinsberg reagent
|
| (ii) | Sulphanilic acid | (a) |
Zwitter ion (dipolar ion)
|
| (iii) | Alkyl diazonium salts | (d) |
Conversion to alcohols \[\ce{R - N+2X- ->[H2O] ROH}\] |
| (iv) | Aryl diazonium salts | (c) | Dyes |
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संबंधित प्रश्न
Illustrate the following reaction giving suitable example in each case: Diazotisation
Write equations of the following reactions:
Acetylation of aniline
Arenium ion involved in the bromination of aniline is:
(i)

(ii)

(iii)

(iv)

Why does acetylation of –NH2 group of aniline reduce its activating effect?
Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].
Why is aniline soluble in aqueous HCl?
How will you carry out the following conversions?
toluene `->` p-toluidine
Predict the reagent or the product in the following reaction sequence.

Which of the following is true characteristic feature of aniline?
Benzene diazonium chloride is a ______.
Consider the following compounds:
(i) p-methyl aniline
(ii) N, N-dimethylaniline
(iii) N-ethyl aniline
(iv) N-ethyl-N-methyl aniline
The compounds which do not form diazonium salt with ice-colds NaNO2 and HCl are:

Major Product In the above chemical reaction, intermediate "X" and reagent/condition "A" are:
Identify A and B for the following reaction:

What are polymers?
How will the following be converted? (Give chemical equation)
Aniline to benzene diazonium chloride.
Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below:


