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प्रश्न
Why is aniline soluble in aqueous HCl?
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उत्तर
Aniline forms anilinium chloride salt with aqueous HCl which is soluble in water.
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संबंधित प्रश्न
Illustrate the following reaction giving suitable example in each case: Diazotisation
Why is benzene diazonium chloride not stored and is used immediately after its preparation?
Why does acetylation of –NH2 group of aniline reduce its activating effect?
How will you carry out the following conversions?
toluene `->` p-toluidine
How will you carry out the following conversions?
p-toluidine diazonium chloride `→` p-toluic acid
Match the compounds given in Column I with the items given in Column II.
| Column I | Column II | ||
| (i) | Benzene sulphonyl chloride | (a) | Zwitter ion |
| (ii) | Sulphanilic acid | (b) | Hinsberg reagent |
| (iii) | Alkyl diazonium salts | (c) | Dyes |
| (iv) | Aryl diazonium salts | (d) | Conversion to alcohols |
Predict the reagent or the product in the following reaction sequence.
Which of the following statement about primary amines is false?
In order to distinguish between C2H5NHz and C6H5NHz, which of the following reagents is useful?
Which of the following is true characteristic feature of aniline?
Benzene diazonium chloride is a ______.
Consider the following compounds:
(i) p-methyl aniline
(ii) N, N-dimethylaniline
(iii) N-ethyl aniline
(iv) N-ethyl-N-methyl aniline
The compounds which do not form diazonium salt with ice-colds NaNO2 and HCl are:
Major Product In the above chemical reaction, intermediate "X" and reagent/condition "A" are:
Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0 °C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:
Identify A and B for the following reaction:
What are polymers?
Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below:
