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Obtain the equation for resultant intensity due to interference of light.

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प्रश्न

Obtain the equation for resultant intensity due to interference of light.

संख्यात्मक
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उत्तर

  1. The phenomenon of addition or superposition of two light waves which produces increase in intensity at some points and a decrease in intensity at some other points is called interference of light.
  2. Let us consider two light waves from the two sources S1 and S2 meeting at a point P as shown
  3. The wave from S1 at an instant t and P is, y1 = a1 sin ωt
    The wave from S2 an instant t at P is
    y2 = a2 sin(ωt + Φ)

    Superposition principle
  4. The two waves have different amplitudes a1 and a2, same angular frequency ω’ and a phase difference of Φ between them. The resultant displacement will be given by.
    y = y1 + y2 = a1 sin ωt + a1 sin2 (ωt + Φ) y = A sin (ωt + Φ)
    Where, A = `sqrt("a"_1^2 + "a"_2^2 + 2"a"_1"a"_2 cos phi)`  .....(1)
    `theta = tan^-1  ("a"_2 sin phi)/("a"_1 + "a"_2 cos phi)`   ......(2)
  5. The resultant amplitude is maximum.
    Amax = `sqrt(("a"_1 + "a"_2)^2)`;
    when Φ = 0, ±2π, ± 4π …….(3)
  6. The resultant amplitude is minimum.
    Amin = `sqrt(("a"_1 - "a"_2)^2)`;
    when Φ = 0, ±π, ± 3π ± 5π …..(4)
  7. The intensity of light is proportional to the square of amplitude.
  8. I α A2 ……(5)
    Now equation (1) becomes
    I α I1 + I2 + 2`sqrt("I"_1"I"_2)` cos Φ .(6)
  9. 9. If the phase difference, Φ = 0, ± 2π, ± 4π., it corresponds to the condition for maximum intensity of light called as constructive interference.
  10. The resultant maximum intensity is,
    Imax α (a1 + a2)2 …….(7)
  11. If the phase difference, Φ = + π, ± 3π, ± 5π …., it corresponds to the condition for the minimum intensity of light called destructive interference.
  12. The resultant minimum intensity is Imin α
    (a1 – a2)2 α I1 + I2 – 2`sqrt("I"_1"I"_2)`   ......(8)
    As a special case, if a1 = a2 = a, then equation (1) becomes,
    A = `sqrt(2"a"^2 + 2"a"^2 cos phi)`
    = `sqrt(2"a"^2 (1 + cos phi))`
    = `sqrt(2"a"^2 2cos^2 (phi//2))`
  13. A = 2 a cos(Φ/2) ….(9)

    I α 4a2 cos2 (Φ/2) [∴ I α A2] ……(10)
    I α 4 I0 cos2 (Φ/ 2) [ΦI0 α a2] …….(11)
    IMax = 4I0 when, Φ = o, ± 2π, 4π  …..(12)
    Imin = 0 when, Φ = ± π, ± 3π, ± 5π …..(13)
    Conclusion:
    The phase difference between the two waves decides the intensity of light meet at a point.

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अध्याय 7: Wave Optics - Evaluation [पृष्ठ १०४]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 7 Wave Optics
Evaluation | Q 3. | पृष्ठ १०४

संबंधित प्रश्न

Write the important characteristic features by which the interference can be distinguished from the observed diffraction pattern.


How does the angular separation between fringes in single-slit diffraction experiment change when the distance of separation between the slit screens is doubled?


A narrow slit S transmitting light of wavelength λ is placed a distance d above a large plane mirror, as shown in the following figure. The light coming directly from the slit and that coming after the reflection interfere at a screen ∑ placed at a distance D from the slit. (a) What will be the intensity at a point just above the mirror, i.e. just above O? (b) At what distance from O does the first maximum occur?


Describe Young's double-slit interference experiment and derive conditions for occurrence of dark and bright fringes on the screen. Define fringe width and derive a formula for it.


Draw a neat labelled ray diagram of the Fresnel Biprism experiment showing the region of interference. 


Explain constructive and destructive interference with the help of a diagram?


Discuss the interference in thin films and obtain the equations for constructive and destructive interference for transmitted and reflected light.


In Young's double slit experiment green light is incident on the two slits. The interference pattern is observed on a screen. Which one of the following changes would cause the observed fringes to be more closely spaced?


In Young's double-slit experiment, in an interference pattern, a second minimum is observed exactly in front of one slit. The distance between the two coherent sources is 'd' and the distance between source and screen is 'D'. The wavelength of the light source used is ______


A graph is plotted between the fringe-width Z and the distance D between the slit and eye-piece, keeping other adjustment same. The correct graph is

A.
B.
C.
D.

In a Young's experiment, two coherent sources are placed 0.60 mm apart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of 1 mm from the central fringe, the wavelength of monochromatic light used would be ____________.


Two sources of light 0.5 mm apart are placed at a distance of 2.4 m and wavelength of light is 5000 Å. The phase difference between the two light waves interfering on the screen at a point at a distance 3 mm from central bright band is ____________.


In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide with nth red bright band for the same setting is ______.


Two coherent light sources of intensity ratio 'n' are employed in an interference experiment. The ratio of the intensities of the maxima and minima in the interference pattern is (I1 > I2).


In biprism experiment, the 4th dark band is formed opposite to one of the slits. The wavelength of light used is ______.


Two identical light sources s1 and s2 emit light of same wavelength `lambda`. These light rays will exhibit interference if their ______.


The graph shows the variation of fringe width (β) versus distance of the screen from the plane of the slits (D) in Young's double-slit experiment Keeping other parameters the same. The wavelength of light used can be calculated as d = distance between the slits ______ 

 


In Young's double slit experiment, for wavelength λ1 the nth bright fringe is obtained at a point P on the screen. Keeping the same setting, source of light is replaced by wavelength λ2 and now (n + 1)th bright fringe is obtained at the same point P on the screen. The value of n is ______.


In Young's double-slit experiment, the distance between the slits is 3 mm and the slits are 2 m away from the screen. Two interference patterns can be obtained on the screen due to light of wavelength 480 nm and 600 run respectively. The separation on the screen between the 5th order bright fringes on the two interference patterns is ______


In an interference experiment, the intensity at a point is `(1/4)^"th"` of the maximum intensity. The angular position of this point is at ____________. 
(cos 60° = 0.5, `lambda` = wavelength of light, d = slit width)


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