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प्रश्न
Name the electrophile produced in the reaction of benzene with benzoyl chloride in the presence of anhydrous \[\ce{AlCl3}\]. Name the reaction also.
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उत्तर
\[\begin{array}{cc}
\phantom{}\ce{O}\phantom{.......................}\ce{O}\phantom{...............................}\\
\phantom{}||\phantom{.......................}||\phantom{...............................}\\
\ce{C6HC - Cl + AlCl3 -> C6H5\overset{δ+}{C - Cl} = \overset{δ-}{Alcl3} -> C6H5Co+ + AlCl4}
\end{array}\]
Friedel–Crafts acylation reaction.
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संबंधित प्रश्न
How will you bring about the following conversion?
Benzoyl chloride to benzaldehyde.
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
p-Nitrobenzaldehyde
Esters react with DIBAL-H to produce:
The oxidation of toluene to benzoic acid can be done using which of the following reagents.
Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.
Match the example given in Column I with the name of the reaction in Column II.
| Column I (Example) |
Column II (Reaction) |
||
| (i) | \[\begin{array}{cc} \phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H} \end{array}\] |
(a) | Friedel Crafts acylation |
| (ii) |  |
(b) | HVZ reaction |
| (iii) |  |
(c) | Aldol condensation |
| (iv) | \[\begin{array}{cc} \ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\ce{Br} \end{array}\] |
(d) | Cannizaro’s reaction |
| (v) | \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] | (e) | Rosenmund’s reductio |
| (vi) | \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] | (f) | Stephen’s reaction |
An alkene ‘A’ (Mol. formula \[\ce{C5H10}\]) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with \[\ce{I2}\] and \[\ce{NaOH}\]. Compound ‘C’ does not give Fehling’s test but forms iodoform. Identify the compounds A, B and C. Write the reaction for ozonolysis and formation of iodoform from B and C.
An aromatic compound ‘A’ (Molecular formula \[\ce{C8H8O}\]) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollen’s or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula \[\ce{C7H6O2}\]), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all the reactions involved.
In the chromyl chloride test, the final step results in the formation of a yellow precipitate of the following:
When 2 – hydroxyl benzoic acid distilled with zinc dust, it give
The general formula CnH2NO2 could be for open chain
Aldehydes are the first oxidation products of ______.
The intermediate compound ‘X’ in the following chemical reaction is:
The oxidation of toluene to benzaldehyde by chromyl chloride is called ______.
Convert the following:
Benzoic acid to Benzaldehyde.
Explain the following reactions:
Stephan reaction
Predict the reagent for carrying out the following transformations:
Benzoyl chloride to Benzaldehyde
The reaction of benzene with CO and HCl in the presence of anhydrous AlCl3 gives ______.
Account for the following:
N-ethylbenzene sulphonyl amide is soluble in alkali.
