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प्रश्न
Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.
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उत्तर
In (ii) reaction, it readily undergoes further alkylation to produce polysubs- tituted derivative.
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संबंधित प्रश्न
Write the chemical equations to illustrate the following name reactions : Rosenmund reduction
Predict the product of the following reaction:
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
p-Nitrobenzaldehyde
Write the reaction involved in the Stephen reduction
Aldehydes are produced on reduction of the following by DIBAL-H:
The oxidation of toluene to benzoic acid can be stopped at the aldehyde stage to give benzaldehyde. The reagent used for the purpose is one of the following.
The oxidation of toluene to benzoic acid can be done using which of the following reagents.
Can Gatterman-Koch reaction be considered similar to Friedel Craft’s acylation? Discuss.
Match the acids given in Column I with their correct IUPAC names given in Column II.
| Column I (Acids) |
Column II (IUPAC names) |
||
| (i) | Phthalic acid | (a) | Hexane-1,6-dioic acid |
| (ii) | Oxalic acid | (b) | Benzene-1,2-dicarboxylic acid |
| (iii) | Succinic acid | (c) | Pentane-1,5-dioic acid |
| (iv) | Adipic acid | (d) | Butane-1,4-dioic acid |
| (v) | Glutaric acid | (e) | Ethane-1,2-dioic acid |
An alkene ‘A’ (Mol. formula \[\ce{C5H10}\]) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with \[\ce{I2}\] and \[\ce{NaOH}\]. Compound ‘C’ does not give Fehling’s test but forms iodoform. Identify the compounds A, B and C. Write the reaction for ozonolysis and formation of iodoform from B and C.
An aromatic compound ‘A’ (Molecular formula \[\ce{C8H8O}\]) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollen’s or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula \[\ce{C7H6O2}\]), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all the reactions involved.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\] obtained by chlorination of n-butane, will be
The reaction
The strongest base among the following
Aldehydes are the first oxidation products of ______.
The oxidation of toluene to benzaldehyde by chromyl chloride is called ______.
Convert the following:
Benzoic acid to Benzaldehyde.
Explain the following reactions:
Stephan reaction
Reagent used to convert allyl alcohol to acrolein is ______.
An organic compound with molecular formula \[\ce{C7H7NO2}\] exists in three isomeric forms, the isomer ‘A’ has the highest melting point of the three. ‘A’ on reduction gives compound ‘B’ with molecular formula \[\ce{C7H9N}\]. ‘B’ on treatment with \[\ce{NaNO2/HCl}\] at 0-5° C to form compound ‘C’. On treating C with \[\ce{H3PO2}\], it gets converted to D with formula \[\ce{C7H8}\], which on further reaction with \[\ce{CrO2Cl2}\] followed by hydrolysis forms ‘E’ \[\ce{C7H6O}\]. Write the structure of compounds A to E. Write the chemical equations involved.
