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प्रश्न
Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.
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उत्तर
In (ii) reaction, it readily undergoes further alkylation to produce polysubs- tituted derivative.
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संबंधित प्रश्न
Write the product in the following reaction
Write the product in the following reaction:
Write the reaction involved in the Stephen reduction
When 0.4 g of acetic acid is dissolved in 40 g of benzene, the freezing point of the solution is lowered by 0.45 K. Calculate the degree of association of acetic acid. Acetic acid forms dimer when dissolved in benzene.
(Kf for benzene = 5.12 K kg mol−1, at. wt. C = 12, H = 1, O = 16)
Ozonolysis of alkenes followed by the reaction with zinc dust and water gives ____________ depending on the substitution pattern of the alkene.
Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called:
Can Gatterman-Koch reaction be considered similar to Friedel Craft’s acylation? Discuss.
Match the acids given in Column I with their correct IUPAC names given in Column II.
| Column I (Acids) |
Column II (IUPAC names) |
||
| (i) | Phthalic acid | (a) | Hexane-1,6-dioic acid |
| (ii) | Oxalic acid | (b) | Benzene-1,2-dicarboxylic acid |
| (iii) | Succinic acid | (c) | Pentane-1,5-dioic acid |
| (iv) | Adipic acid | (d) | Butane-1,4-dioic acid |
| (v) | Glutaric acid | (e) | Ethane-1,2-dioic acid |
Match the example given in Column I with the name of the reaction in Column II.
| Column I (Example) |
Column II (Reaction) |
||
| (i) | \[\begin{array}{cc} \phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H} \end{array}\] |
(a) | Friedel Crafts acylation |
| (ii) |  |
(b) | HVZ reaction |
| (iii) |  |
(c) | Aldol condensation |
| (iv) | \[\begin{array}{cc} \ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\ce{Br} \end{array}\] |
(d) | Cannizaro’s reaction |
| (v) | \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] | (e) | Rosenmund’s reductio |
| (vi) | \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] | (f) | Stephen’s reaction |
An alkene ‘A’ (Mol. formula \[\ce{C5H10}\]) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with \[\ce{I2}\] and \[\ce{NaOH}\]. Compound ‘C’ does not give Fehling’s test but forms iodoform. Identify the compounds A, B and C. Write the reaction for ozonolysis and formation of iodoform from B and C.
In the chromyl chloride test, the final step results in the formation of a yellow precipitate of the following:
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\] obtained by chlorination of n-butane, will be
The reaction
When 2 – hydroxyl benzoic acid distilled with zinc dust, it give
Convert the following:
Benzoic acid to Benzaldehyde.
Predict the reagent for carrying out the following transformations:
Benzoyl chloride to Benzaldehyde
Assertion (A): Strong oxidising agents oxidise toluene and its derivatives to benzoic acids.
Reason (R): It is possible to stop the oxidation of toluene at the aldehyde stage with suitable reagents.
Select the most appropriate answer from the options given below:
Account for the following:
Reduction of nitrobenzene using Fe and HCl is preferred over Sn and HCl.
Write the name of the reaction, structure and IUPAC name of the product formed when:
CH3CH2CN reacts with stannous chloride in the presence of hydrochloric acid, followed by hydrolysis.
