हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Match the example given in Column I with the name of the reaction in Column II. Column I (Example) Column II (Reaction) (i) ...O..............................O...||..............................||CH - Chemistry

Advertisements
Advertisements

प्रश्न

Match the example given in Column I with the name of the reaction in Column II.

  Column I
(Example)
  Column II
(Reaction)
(i) \[\begin{array}{cc}
\phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\
\phantom{...}||\phantom{..............................}||\phantom{}\\
\ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H}
\end{array}\]
(a) Friedel Crafts acylation
(ii) (b) HVZ reaction
(iii) (c) Aldol condensation
(iv) \[\begin{array}{cc}
\ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\
\phantom{.....................}|\\
\phantom{.......................}\ce{Br}
\end{array}\]
(d) Cannizaro’s reaction
(v) \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] (e) Rosenmund’s reductio
(vi) \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] (f) Stephen’s reaction
जोड़ियाँ मिलाइएँ
Advertisements

उत्तर

  Column I
(Example)
  Column II
(Reaction)
(i) \[\begin{array}{cc}
\phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\
\phantom{...}||\phantom{..............................}||\phantom{}\\
\ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H}
\end{array}\]
(e) Rosenmund’s reductio
(ii) (d) Cannizaro’s reaction
(iii) (a) Friedel Crafts acylation
(iv) \[\begin{array}{cc}
\ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\
\phantom{.....................}|\\
\phantom{.......................}\ce{Br}
\end{array}\]
(b) HVZ reaction
(v) \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] (f) Stephen’s reaction
(vi) \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] (c) Aldol condensation
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Aldehydes, Ketones and Carboxylic Acids - Multiple Choice Questions (Type - I) [पृष्ठ १७४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 12 Aldehydes, Ketones and Carboxylic Acids
Multiple Choice Questions (Type - I) | Q 41 | पृष्ठ १७४

संबंधित प्रश्न

Predict the product of the following reaction:


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

p-Nitrobenzaldehyde


Write the reaction involved in the Stephen reduction


Esters react with DIBAL-H to produce:


The oxidation of toluene to benzoic acid can be done using which of the following reagents.


Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.


Match the common names given in Column I with the IUPAC names given in Column II.

  Column I
(Common names)
  Column II
(IUPAC names)
(i) Cinnamaldehyde (a) Pentanal
(ii) Acetophenone (b) Prop-2-enal
(iii) Valeraldehyde (c) 4-Methylpent-3-en-2-one
(iv) Acrolein (d) 3-Phenylprop-2-enal
(v) Mesityl oxide (e) 1-Phenylethanone

An aromatic compound ‘A’ (Molecular formula \[\ce{C8H8O}\]) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollen’s or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula \[\ce{C7H6O2}\]), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all the reactions involved.


What is the name of the given reaction of preparation of aldehyde?

\[\ce{C3COCl ->[H2][Pd/BaSO4] CH3CHO + HCl}\]


\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\]  obtained by chlorination of n-butane, will be


The number of chiral carbon in glucose is:-


When 2 – hydroxyl benzoic acid distilled with zinc dust, it give


The general formula CnH2NO2 could be for open chain


Aldehydes are the first oxidation products of ______.


The reagent in friedel - craft reaction is:


The reaction of benzene with CO and HCl in the presence of anhydrous AlCl3 gives ______.


An organic compound with molecular formula \[\ce{C7H7NO2}\] exists in three isomeric forms, the isomer ‘A’ has the highest melting point of the three. ‘A’ on reduction gives compound ‘B’ with molecular formula \[\ce{C7H9N}\]. ‘B’ on treatment with \[\ce{NaNO2/HCl}\] at 0-5° C to form compound ‘C’. On treating C with \[\ce{H3PO2}\], it gets converted to D with formula \[\ce{C7H8}\], which on further reaction with \[\ce{CrO2Cl2}\] followed by hydrolysis forms ‘E’ \[\ce{C7H6O}\]. Write the structure of compounds A to E. Write the chemical equations involved.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×