Advertisements
Advertisements
प्रश्न
Match the common names given in Column I with the IUPAC names given in Column II.
| Column I (Common names) |
Column II (IUPAC names) |
||
| (i) | Cinnamaldehyde | (a) | Pentanal |
| (ii) | Acetophenone | (b) | Prop-2-enal |
| (iii) | Valeraldehyde | (c) | 4-Methylpent-3-en-2-one |
| (iv) | Acrolein | (d) | 3-Phenylprop-2-enal |
| (v) | Mesityl oxide | (e) | 1-Phenylethanone |
Advertisements
उत्तर
| Column I (Common names) |
Column II (IUPAC names) |
||
| (i) | Cinnamaldehyde | (d) | 3-Phenylprop-2-enal |
| (ii) | Acetophenone | (e) | 1-Phenylethanone |
| (iii) | Valeraldehyde | (a) | Pentanal |
| (iv) | Acrolein | (b) | Prop-2-enal |
| (v) | Mesityl oxide | (c) | 4-Methylpent-3-en-2-one |
Explanation:
| (Common names) | Structure | (IUPAC names) |
| (i) Cinnamaldehyde |  |
3-Phenylprop-2-enal |
| (ii) Acetophenone |  |
1-Phenylethanone |
| (iii) Valeraldehyde |  |
Pentanal |
| (iv) Acrolein |  |
Prop-2-enal |
| (v) Mesityl oxide |  |
4-Methylpent-3-en-2- one |
APPEARS IN
संबंधित प्रश्न
How will you bring about the following conversion?
Benzoyl chloride to benzaldehyde.
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
p-Nitrobenzaldehyde
Esters react with DIBAL-H to produce:
Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.
Can Gatterman-Koch reaction be considered similar to Friedel Craft’s acylation? Discuss.
Match the example given in Column I with the name of the reaction in Column II.
| Column I (Example) |
Column II (Reaction) |
||
| (i) | \[\begin{array}{cc} \phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H} \end{array}\] |
(a) | Friedel Crafts acylation |
| (ii) |  |
(b) | HVZ reaction |
| (iii) |  |
(c) | Aldol condensation |
| (iv) | \[\begin{array}{cc} \ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\ce{Br} \end{array}\] |
(d) | Cannizaro’s reaction |
| (v) | \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] | (e) | Rosenmund’s reductio |
| (vi) | \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] | (f) | Stephen’s reaction |
An alkene ‘A’ (Mol. formula \[\ce{C5H10}\]) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with \[\ce{I2}\] and \[\ce{NaOH}\]. Compound ‘C’ does not give Fehling’s test but forms iodoform. Identify the compounds A, B and C. Write the reaction for ozonolysis and formation of iodoform from B and C.
What is the name of the given reaction of preparation of aldehyde?
\[\ce{C3COCl ->[H2][Pd/BaSO4] CH3CHO + HCl}\]
In the chromyl chloride test, the final step results in the formation of a yellow precipitate of the following:
The reaction
Aldehydes are the first oxidation products of ______.
The reagent in friedel - craft reaction is:
Assertion (A): Strong oxidising agents oxidise toluene and its derivatives to benzoic acids.
Reason (R): It is possible to stop the oxidation of toluene at the aldehyde stage with suitable reagents.
Select the most appropriate answer from the options given below:
Account for the following:
N-ethylbenzene sulphonyl amide is soluble in alkali.
Account for the following:
Reduction of nitrobenzene using Fe and HCl is preferred over Sn and HCl.
Write the name of the reaction, structure and IUPAC name of the product formed when:
CH3CH2CN reacts with stannous chloride in the presence of hydrochloric acid, followed by hydrolysis.
