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Life of bulbs produced by two factories A and B are given below: Length of life(in hours) Factory A(Number of bulbs) Factory B(Number of bulbs) 550 – 650 10 8 650 – 750 22 60 750 – 850 52 24 850 – 95 - Mathematics

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प्रश्न

Life of bulbs produced by two factories A and B are given below:

Length of life
(in hours)
Factory A
(Number of bulbs)
Factory B
(Number of bulbs)
550 – 650 10 8
650 – 750 22 60
750 – 850 52 24
850 – 950 20 16
950 – 1050 16 12
  120 120

The bulbs of which factory are more consistent from the point of view of length of life?

सारिणी
योग
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उत्तर

Here h = 100

Let A (assumed mean) = 800.

Length of life
(in hour)
Mid values
`(x_i)`
`y_i = (x_i - A)/10` Factory A Factory B
      `f_i` `f_iy_i` `f_iy_i^2` `f_i` `f_iy_i` `f_iy_i^2`
550 – 650 600 –2 10 –20 40 8 –16 32
650 – 750 700 –1 22 –22 22 60 – 60 60
750 – 850 800 0 52 0 0 24 0 0
850 – 950 900 1 20 20 20 16 16 16
950 – 1050 1000 2 16 32 64 12 24 48
      120 10 146 120 –36 156

For factory A

Mean `(barx) = 800 + 10/120 xx 100` = 816.67 hours

S.D. = `100/120 sqrt(120(146) - 100)` = 109.98 

Therefore, Coefficient of variation (C.V.) = `(S.D.)/barx xx 100`

= `109.98/816.67 xx 100`

= 13.47

For factory B

Mean = `800 + (-36)/120 100` = 770

S.D. = `100/120 sqrt(120(156) - (-36)^2)` = 110

Therefore, Coefficient of variation = `(S.D.)/"Mean" xx 100`

= `110/770 xx 100`

= 14.29

Since C.V. of factory B > C.V. of factory A

⇒ Factory B has more variability which means bulbs of factory A are more consistent.

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अध्याय 15: Statistics - Solved Examples [पृष्ठ २७६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 15 Statistics
Solved Examples | Q 6 | पृष्ठ २७६

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