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Integrate the functions: 11-tanx

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प्रश्न

Integrate the functions:

`1/(1 - tan x)`

योग
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उत्तर

Let `I = int 1/ (1 - tan x)dx = int 1/ (1 - sin x/ cos x) dx`

`= int cos x/ (cos x - sin x) dx = 1/2 int (2 cos x)/ (cos x - sin x) dx`

`1/2 int  ((cos x - sin x) - (-sin x - cos x))/(cos x - sin x)`

`1/2 int 1 dx - 1/2 int  (-sin x - cos x)/ (cos x - sin x) dx`

`x/2 - 1/2 int (-sin x - cos x)/ (cos x - sin x) dx + C_1`

`I = x/2 - 1/2 I_1 + C_1`           ....(i)

Where, `I_1 = int (-sinx - cos x)/(cos x - sin x) dx`

Put cos x - sin x = t

⇒ (-sin x - cos x) dx = dt

`I_1 = int dt/t = log |t| + C_2`

= log | cos x - sin x| + C2                    ...(ii)

From (i) and (ii), we get

⇒ `I = x/2 - 1/2 log |cos x - sin x| + C`

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अध्याय 7: Integrals - Exercise 7.2 [पृष्ठ ३०५]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.2 | Q 33 | पृष्ठ ३०५

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