हिंदी

In any Δ ABC, prove the following: a sin A - b sin B = c sin (A - B)

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प्रश्न

In any Δ ABC, prove the following:

a sin A - b sin B = c sin (A - B)

योग
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उत्तर

By sine rule,

`"a"/("sin A") = "b"/("sin B") = "c"/("sin C") = "k"`

∴ a = k sin A, b = k sin B, c = k sin C

LHS =  a sin A - b sin B

= k sin A. sin A - k sin B. sin B

= k (sin2 A - sin2 B)

= k (sin A + sin B)(sin A - sin B)

`= "k" xx 2 sin  (("A + B")/2). cos (("A - B")/2) xx 2 cos (("A + B")/2). sin (("A - B")/2)`

`= "k" xx 2 sin  (("A + B")/2). cos (("A + B")/2) xx 2 sin (("A - B")/2). cos (("A - B")/2)`

= k × sin (A + B) × sin (A - B)

= k sin (π - C). sin (A - B)  … [∴ A + B + C = π]

= k sin C. sin (A - B)

= c sin (A - B)

= RHS.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 11.1 | पृष्ठ १०९

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