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Show that tan-1(15)+tan-1(17)+tan-1(13)+tan-1(18)=π4.

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प्रश्न

Show that

`tan^-1(1/5) + tan^-1(1/7) + tan^-1(1/3) + tan^-1 (1/8) = pi/4.`

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उत्तर

LHS = `tan^-1(1/5) + tan^-1(1/7) + tan^-1(1/3) + tan^-1 (1/8)`

`= tan^-1 [(1/5 + 1/7)/(1 - 1/5 xx 1/7)] + tan^-1 [(1/3+1/8)/(1 - 1/3 xx 1/8)]`

`= tan^-1 ((7 + 5)/(35 - 1)) + tan^-1 ((8 + 3)/(24 - 1))`

`= tan^-1 (12/34) + tan^-1 (11/23)`

`= tan^-1 (6/17) + tan^-1 (11/23)`

`= tan^-1 [(6/17 + 11/23)/(1 - 6/17 xx 11/23)]`

`= tan^-1((138 + 187)/(391 - 66)) = tan^-1 (325/325)`

`= tan^-1 (1) = tan^-1 (tan  pi/4)`

`= pi/4`

= RHS.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 20 | पृष्ठ ११०

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