हिंदी

In any ΔABC, with usual notations, prove that b2 = c2 + a2 – 2ca cos B.

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प्रश्न

In any ΔABC, with usual notations, prove that b2 = c2 + a2 – 2ca cos B.

योग
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उत्तर

Let us take the angle B of ΔABC in standard position,

i.e. B as origin, X-axis along the line BC and the Y-axis perpendicular to the line BC.

In the two figures, ∠B is shown as acute in one and obtuse in the other.

∵ l(BC) = a

∴ C ≡ (a, 0)

Let A ≡ (x, y)

Since l (BA) = c, we have

cos B = `x/c` and sin B = `y/c`

∴ x = c cos B and y = c sin B

∴ A ≡ (c cos B, c sin B)

∴ By the distance formula

b2 = AC2 = (a – c cos B)2 + (0 – c sin B)2

= a2 – 2ca cos B + c2 cos2B + c2 sin2B

=  c2(cos2B + sin2B) + a2 – 2ca cos B

∴ b2 = c2 + a2 – 2ca cos B.

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2013-2014 (March)

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