हिंदी

In ∆ABC, if cos A = sinB2sinC, then ∆ABC is ______.

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प्रश्न

In ∆ABC, if cos A = `(sinB)/(2sinC)`, then ∆ABC is ______.

विकल्प

  • an equilateral triangle

  • a right angled triangle

  • an isosceles triangle

  • an isosceles right angled triangle

MCQ
रिक्त स्थान भरें
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उत्तर

In ∆ABC, if cos A = `(sinB)/(2sinC)`, then ∆ABC is an isosceles triangle.

Explanation:

cos A = `(sinB)/(2sinC)`

∴ cos A = `(bk)/(2ck)`   ....(Sine rule)

Also, `(b^2 + c^2 - a^2)/(2bc) = b/(2c)`   ....(Cosine rule)

∴ `(b^2 + c^2 - a^2)/b` = b

∴ b2 + c2 – a2 = b2

∴ c2 = a2

`\implies` c = a

`\implies` ∆ABC is an isosceles triangle

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अध्याय 1.3: Trigonometric Functions - MCQ

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