Advertisements
Advertisements
प्रश्न
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
Advertisements
उत्तर
∠A + ∠B + ∠C = 180°
⇒ 100° + ∠B + ∠B = 180°
⇒ 2∠B = 180° 100°
∠B = `(80°)/2`
∠B = 40°
∠C = ∠B = 40°
APPEARS IN
संबंधित प्रश्न
Is the following statement true and false :
A triangle can have two obtuse angles.
The bisects of exterior angle at B and C of ΔABC meet at O. If ∠A = x°, then ∠BOC =
In a triangle PQR, ∠P = 60° and ∠Q = ∠R, find ∠R.
Find the unknown marked angles in the given figure:
Can a triangle together have the following angles?
55°, 55° and 80°
Classify the following triangle according to sides:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
17 cm, 7 cm, 8 cm
S is any point on side QR of a ∆PQR. Show that: PQ + QR + RP > 2PS.
O is a point in the interior of a square ABCD such that OAB is an equilateral triangle. Show that ∆OCD is an isosceles triangle.
In the following figure, AB = BC and AD = BD = DC. The number of isosceles triangles in the figure is ______.
