Advertisements
Advertisements
प्रश्न
In ∆ABC, ∠A = ∠B = 62° ; find ∠C.
Advertisements
उत्तर
∠A + ∠B + ∠C= 180°
⇒ 62° + 62° + ∠C = 180°
⇒ 124° + ∠C = 180°
⇒ ∠C = 180° – 124°
⇒∠C = 56°
APPEARS IN
संबंधित प्रश्न
AB is a line segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB.
Compute the value of x in the following figure:

If two acute angles of a right triangle are equal, then each acute is equal to
Side BC of a triangle ABC has been produced to a point D such that ∠ACD = 120°. If ∠B = \[\frac{1}{2}\]∠A is equal to
Find the value of the angle in the given figure:

Calculate the unknown marked angles of the following figure :

Can a triangle together have the following angles?
85°, 95° and 22°
The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is
In the following figure, l || m and M is the mid-point of a line segment AB. Show that M is also the mid-point of any line segment CD, having its end points on l and m, respectively.

Can we have two acute angles whose sum is a right angle? Why or why not?
