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प्रश्न
If Young's double slit experiment is performed in water, _________________ .
विकल्प
the fringe width will decrease
the fringe width will increase
the fringe width will remain unchanged
there will be no fringe
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उत्तर
the fringe width will decrease
As fringe width is proportional to the wavelength and wavelength of light is inversely proportional to the refractive index of the medium,
Here,
\[\lambda_M = \lambda/\eta\]
\[ \lambda_M = \text{wavelength in medium}\]
\[\lambda = \text{wavelength in vacuum}\]
\[\eta = \text{refractive index of medium}\]
Hence, fringe width decreases when Young's double slit experiment is performed under water.
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संबंधित प्रश्न
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In Young’s double slit experiment using monochromatic light of wavelength λ, the intensity of light at a point on the screen where path difference is λ, is K units. Find out the intensity of light at a point where path difference is λ/3.
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(ii) destructive interference at a point on the screen.
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A double slit S1 − S2 is illuminated by a coherent light of wavelength \[\lambda.\] The slits are separated by a distance d. A plane mirror is placed in front of the double slit at a distance D1 from it and a screen ∑ is placed behind the double slit at a distance D2 from it (see the following figure). The screen ∑ receives only the light reflected by the mirror. Find the fringe-width of the interference pattern on the screen.
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ASSERTION (A): In an interference pattern observed in Young's double slit experiment, if the separation (d) between coherent sources as well as the distance (D) of the screen from the coherent sources both are reduced to 1/3rd, then new fringe width remains the same.
REASON (R): Fringe width is proportional to (d/D).
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