हिंदी

If the vertices of a triangle have integral coordinates, then the triangle can not be equilateral.

Advertisements
Advertisements

प्रश्न

If the vertices of a triangle have integral coordinates, then the triangle can not be equilateral.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
Advertisements

उत्तर

This statement is True.

Explanation:

Let A(x1, y1), B(x2, y2) and C(x3, y3) be the vertices of a triangle ABC, where xi, yi, i = 1, 2, 3 are integers.

Then, the area of ΔABC is given by

Δ = `1/2 [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]`

= A rational number   ......[∵ xi, yi, are integers]

If possible, let the triangle ANC be an equilateral triangle

Then its area is given by

Δ = `sqrt(3)/4 ("side")^2 = sqrt(3)/4 (AB)^2`  ......[∵ AB = BC = CA]

= `sqrt(3)/4 (a  "positive integer")`   .....[∵ verticles are integral∴ AB2 is a integer]

= an irrational number

This is a contradiction to the fact that the area is a rational number.

Hence, the triangle cannot be equilateral.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Straight Lines - Exercise [पृष्ठ १८३]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 10 Straight Lines
Exercise | Q 48 | पृष्ठ १८३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the angle between the x-axis and the line joining the points (3, –1) and (4, –2).


If three point (h, 0), (a, b) and (0, k) lie on a line, show that `q/h + b/k = 1`


Find the equation of the lines through the point (3, 2) which make an angle of 45° with the line x –2y = 3.


Find the slope of a line passing through the following point:

 (−3, 2) and (1, 4)


Find the slope of a line passing through the following point:

(3, −5), and (1, 2)


Using the method of slope, show that the following points are collinear A (4, 8), B (5, 12), C (9, 28).


What is the value of y so that the line through (3, y)  and (2, 7) is parallel to the line through (−1, 4) and (0, 6)?


What can be said regarding a line if its slope is positive ?


Show that the line joining (2, −3) and (−5, 1) is parallel to the line joining (7, −1) and (0, 3).


Without using Pythagoras theorem, show that the points A (0, 4), B (1, 2) and C (3, 3) are the vertices of a right angled triangle.


If three points A (h, 0), P (a, b) and B (0, k) lie on a line, show that: \[\frac{a}{h} + \frac{b}{k} = 1\].


By using the concept of slope, show that the points (−2, −1), (4, 0), (3, 3) and (−3, 2) are the vertices of a parallelogram.


Find the equation of a straight line with slope 2 and y-intercept 3 .


Find the equation of a straight line with slope −2 and intersecting the x-axis at a distance of 3 units to the left of origin.


Find the equation of a line which is perpendicular to the line joining (4, 2) and (3, 5) and cuts off an intercept of length 3 on y-axis.


Find the equation of the perpendicular to the line segment joining (4, 3) and (−1, 1) if it cuts off an intercept −3 from y-axis.


Find the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.


Prove that the straight lines (a + b) x + (a − b ) y = 2ab, (a − b) x + (a + b) y = 2ab and x + y = 0 form an isosceles triangle whose vertical angle is 2 tan−1 \[\left( \frac{a}{b} \right)\].


Show that the line a2x + ay + 1 = 0 is perpendicular to the line x − ay = 1 for all non-zero real values of a.


Write the coordinates of the image of the point (3, 8) in the line x + 3y − 7 = 0.


The equation of the line with slope −3/2 and which is concurrent with the lines 4x + 3y − 7 = 0 and 8x + 5y − 1 = 0 is


If m1 and m2 are slopes of lines represented by 6x2 - 5xy + y2 = 0, then (m1)3 + (m2)3 = ?


Find the equation of the straight line passing through (1, 2) and perpendicular to the line x + y + 7 = 0.


If the slope of a line passing through the point A(3, 2) is `3/4`, then find points on the line which are 5 units away from the point A.


Find the equation to the straight line passing through the point of intersection of the lines 5x – 6y – 1 = 0 and 3x + 2y + 5 = 0 and perpendicular to the line 3x – 5y + 11 = 0.


A ray of light coming from the point (1, 2) is reflected at a point A on the x-axis and then passes through the point (5, 3). Find the coordinates of the point A.


The coordinates of the foot of the perpendicular from the point (2, 3) on the line x + y – 11 = 0 are ______.


Find the equation of a straight line on which length of perpendicular from the origin is four units and the line makes an angle of 120° with the positive direction of x-axis.


Slope of a line which cuts off intercepts of equal lengths on the axes is ______.


The tangent of angle between the lines whose intercepts on the axes are a, – b and b, – a, respectively, is ______.


Equations of diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1 are ______.


The point (4, 1) undergoes the following two successive transformations: 
(i) Reflection about the line y = x
(ii) Translation through a distance 2 units along the positive x-axis Then the final coordinates of the point are ______.


One vertex of the equilateral triangle with centroid at the origin and one side as x + y – 2 = 0 is ______.


Equations of the lines through the point (3, 2) and making an angle of 45° with the line x – 2y = 3 are ______.


The vertex of an equilateral triangle is (2, 3) and the equation of the opposite side is x + y = 2. Then the other two sides are y – 3 = `(2 +- sqrt(3)) (x - 2)`.


The line `x/a + y/b` = 1 moves in such a way that `1/a^2 + 1/b^2 = 1/c^2`, where c is a constant. The locus of the foot of the perpendicular from the origin on the given line is x2 + y2 = c2.


Line joining the points (3, – 4) and (– 2, 6) is perpendicular to the line joining the points (–3, 6) and (9, –18).


If the line joining two points A (2, 0) and B (3, 1) is rotated about A in anticlockwise direction through an angle of 15°, then the equation of the line in new position is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×