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प्रश्न
If `tan A = 5/12`, find the value of (sin A + cos A) sec A.
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उत्तर
(sin A + cos A) sec A
= `( sinA + cos A ) 1/ cos A`
=`(sinA )/( cos A) + ( cos A)/( cos A)`
= tan A + 1
= `5/12 +1/1`
=` (5+12)/12`
=`17/12`
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