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प्रश्न
If `sin A = 3/4`, calculate sec A.
योग
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उत्तर
Given: `sin A = 3/4`
Step-wise calculation:
1. Use identity cos2 A + sin2 A = 1.
2. `cos A = ±sqrt(1 - sin^2 A)`
= `±sqrt(1 - (3/4)^2)`
= `±sqrt(1 - 9/16)`
= `±sqrt(7/16)`
= `±(sqrt(7))/4`
3. `sec A = 1/cos A`
= `± 1/((sqrt(7))/4)`
= `± 4/sqrt(7)`
= `± (4sqrt(7))/7` ...(Rationalized)
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