Advertisements
Advertisements
प्रश्न
If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?
Advertisements
उत्तर
We have to find the time taken to reach the given final velocity.
We have:
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Acceleration for the entire journey (a) = –5 ms2.
Let the time taken be (t).
We can calculate the time taken using the first equation of motion.
`t = (v-u)/a`
Time taken by the bus to come to rest:
= `(0-20)/-5`
= 4 s
APPEARS IN
संबंधित प्रश्न
A motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 s. What is his acceleration ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How far does it travel in 1 second ?
A ball hits a wall horizontally at 6.0 m s-1. It rebounds horizontally at 4.4 m s-1. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball ?
What do you mean by motion in one direction?
Give one example of following motion :
Uniform velocity
The diagram below shows the pattern of the oil on the road at a constant rate from a moving car. What information do you get from it about the motion of the car.

Express 15 m s-1 in km h-1.
What is the relation between distance and time when the body is moving with variable velocity?
Write down the type of motion of a body along with the A – O – B of the following distance – time graph.

