Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^2 +b^2 +c^2 + 2(ab + bc + ca)`
Given that
`a^2 + b^2 + c^2 = 250 , ab + bc + ca = 3 `
Then we have
`(a+b+c)^2 = a^2 + b^2 + c^2 + 2 (ab + bc+ca)`
`(a+b+c)^2 = 250 + 2.(3)`
`(a+b+c)^2 = 256`
`(a+b+c) =± 16`
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operation.
Subtraction of z from y
Factorize `5sqrt5x^2 + 20x + 3sqrt5`
Factorize the following expressions:
x3 + 6x2 +12x +16
Simplify `(173 xx 173 xx 173 xx 127 xx 127 xx 127)/(173 xx 173 xx 173 xx 127 xx 127 xx 127)`
If x + y = 4 and xy = 2, find the value of x2 + y2
Write the value of 253 − 753 + 503.
Evaluate: (3x - 1)(4x3 - 2x2 + 6x - 3)
Divide: 6x2 + 5x - 6 by 2x + 3
Divide: 8a2 + 4a - 60 by 2a - 5
Express the following as an algebraic expression:
Sum of p and 2r – s minus sum of a and 3n + 4x.
