Advertisements
Advertisements
प्रश्न
If a + b + c = 9 and ab + bc + ca = 40, find a2 + b2 +c2.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^2 +b^2 +c^2 +2(ab +bc+ca)`
Given that
`(a+b+c) = 9,ab + bc + ca = 40`,
Then we have
`(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)`
` ( 9)^2 = a^2 + b^2 + c^2 + 2.( 40) `
`a^2 ++ b^2 + c^2 + 80 = 81`
`a^2 + b^2 + c^2 = 81 - 80
`a^2 + b^2 +c^2 =` 1
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Number 5 added to three times the product of numbers m and n.
Factorize the following expressions:
`8x^2y^3 - x^5`
Factorize the following expressions:
`a^3 - 1/a^3 - 2a + 2/a`
Factorize 8x3 + 27 y3 + 36x2 y + 54xy2
If x2 + y2 = 29 and xy = 2, find the value of x4 + y4 .
The value of \[\frac{(0 . 013 )^3 + (0 . 007 )^3}{(0 . 013 )^2 - 0 . 013 \times 0 . 007 + (0 . 007 )^2}\] is
Write the number of the term of the following polynomial.
ax ÷ 4 – 7
Multiply: (2x - 3y)(2x - 3y)
Divide: 6x2 - xy - 35y2 by 2x - 5y
Write the variables, constant and terms of the following expression
b + 2
