Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 20 and a + b + c = 0, find ab + bc + ca.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^+b^2 +c^2 +2(ab +bc +ca)`
Given that
`a^2 +b^2 +c^2 = 20`
`(a+b+c) = 0`
Then we have
`(a+b+c)^2 = a^2 +b^2 +c^2 +2 (ab +bc + ca)`
`(0)^2 = 20 +2(ab +bc + ca)`
` 20+2(ab +bc + ca) = 0`
`2(ab + bc + ca) = -20`
`(ab +bc + ca) = -10`
APPEARS IN
संबंधित प्रश्न
Factorize `21x^2 - 2x + 1/21`
Factorize 125x3 - 27 y3 - 225x2 y +135xy2
Factorize x3 + 8y3 + 6x2 y +12xy2
Factorize 8a3 – 27b3 – 36a2b + 54ab2
`(x/2 + y + z/3)^3 + (x/2 + (2y)/3 + z)^3 + (-(5x)/6 - y/3 - (4z)/3)^3`
The factors of x3 − 1 + y3 + 3xy are
(x + y)3 − (x − y)3 can be factorized as
Evaluate: (6p2 - 8pq + 2q2) (- 5p)
An algebraic statement which is equivalent to the verbal statement “Three times the sum of ‘x’ and ‘y’ is
The value of 3x2 – 5x + 3 when x = 1 is ______.
