Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 20 and a + b + c = 0, find ab + bc + ca.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^+b^2 +c^2 +2(ab +bc +ca)`
Given that
`a^2 +b^2 +c^2 = 20`
`(a+b+c) = 0`
Then we have
`(a+b+c)^2 = a^2 +b^2 +c^2 +2 (ab +bc + ca)`
`(0)^2 = 20 +2(ab +bc + ca)`
` 20+2(ab +bc + ca) = 0`
`2(ab + bc + ca) = -20`
`(ab +bc + ca) = -10`
APPEARS IN
संबंधित प्रश्न
Factorize xy9 - yx9
Factorize `5sqrt5x^2 + 20x + 3sqrt5`
Factorize `2x^2 + 3sqrt5x + 5`
Factorize the following expressions:
x3y3 + 1
Factorize the following expressions:
`a^3 - 1/a^3 - 2a + 2/a`
If x + y = 4 and xy = 2, find the value of x2 + y2
Divide: x2 + 4xy + 4y2 by x + 2y
Divide: 6x2 + 5x - 6 by 2x + 3
Write in the form of an algebraic expression:
Area of a square is square of its side.
Rohan’s mother gave him ₹ 3xy2 and his father gave him ₹ 5(xy2 + 2). Out of this total money he spent ₹ (10 – 3xy2) on his birthday party. How much money is left with him?
