Advertisements
Advertisements
प्रश्न
Factorize: a2 + b2 + 2 (ab + bc + ca)
Advertisements
उत्तर
= a2 + b2 + 2ab + 2bc + 2ca
Using identity a2 + b2 + 2ab = (a + b)2
We get,
= (a + b)2 + 2bc + 2ca
= (a + b)2 + 2c (b + a)
or (a + b)2 + 2c (a + b)
Taking (a + b) common
= (a + b)(a + b + 2c )
∴ a2 + b2 + 2 (ab + bc + ca) = (a + b)(a + b + 2c)
APPEARS IN
संबंधित प्रश्न
Factorize a2 + 4b2 - 4ab - 4c2
Find the value of x3 + y3 − 12xy + 64, when x + y =−4
The factors of x3 − 7x + 6 are
Divide: 4a2 + 4a + 1 by 2a + 1
Divide: 2a2 - 11a + 12 by a - 4
Express the following as an algebraic expression:
Sum of p and 2r – s minus sum of a and 3n + 4x.
Find the average (A) of four quantities p, q, r and s. If A = 6, p = 3, q = 5 and r = 7; find the value of s.
The rate of planting the grass is ₹ x per square metre. Find the cost of planting the grass on a triangular lawn whose base is y metres and height is z metres.
In the given figure, the length of a green side is given by g and that of the red side is given by p.
Write an expression for the following pattern. Also write an expression if 100 such shapes are joined together.
Will the value of 11x for x = –5 be greater than 11 or less than 11? Explain.
