Advertisements
Advertisements
प्रश्न
Factorize: a2 + b2 + 2 (ab + bc + ca)
Advertisements
उत्तर
= a2 + b2 + 2ab + 2bc + 2ca
Using identity a2 + b2 + 2ab = (a + b)2
We get,
= (a + b)2 + 2bc + 2ca
= (a + b)2 + 2c (b + a)
or (a + b)2 + 2c (a + b)
Taking (a + b) common
= (a + b)(a + b + 2c )
∴ a2 + b2 + 2 (ab + bc + ca) = (a + b)(a + b + 2c)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorize the following expressions:
32a3 + 108b3
8x3 + 27y3 - 216z3 + 108xyz
Multiply: x2 + y2 + z2 − xy + xz + yz by x + y − z
Multiply: x2 + 4y2 + z3 + 2xy + xz − 2yz by x − 2y − z
Factorize: x4 + x2 + 25.
If x3 − 3x2 + 3x − 7 = (x + 1) (ax2 + bx + c), then a + b + c =
Divide: 8a2 + 4a - 60 by 2a - 5
Divide: 15x2 + 31xy + 14y2 by 5x + 7y
The constant term of the expression 2y – 6 is _________
In the expression 2πr, the algebraic variable is ______.
