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प्रश्न
Factorize `2a^2 + 2 sqrt6ab + 3b^2`
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उत्तर
`= (2sqrta)^2 + 2 xx sqrt2a xx sqrt3b + (sqrt3b)^2`
Using identity a2 + 2ab + b2 = (a + b)2
`= (sqrt2a + sqrt3b)^2`
`= (sqrt2a + sqrt3b)(sqrt2a + sqrt3b)`
`∴ 2a^2 + 2sqrt6ab + 3b^2 = (sqrt2a + sqrt3b)(sqrt2a + sqrt3b)`
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