Advertisements
Advertisements
प्रश्न
Factorize a2 + 4b2 - 4ab - 4c2
Advertisements
उत्तर
On rearranging
= a2 - 4ab + 4b2 - 4c2
= (a)2 - 2 x a x 2b + (2b)2 - 4c2
Using identity a2 - 2ab + b2 = (a - b)2
= (a - 2b)2 - 4c2
= (a - 2b)2 - (2c)2
Using identity a2 - b2 = (a + b)(a - b)
= (a - 2b + 2c)(a - 2b - 2c)
∴ a2 + 4b2 - 4ab - 4c2 = (a - 2b + 2c)(a - 2b - 2c)
APPEARS IN
संबंधित प्रश्न
Factorize: `a^2 x^2 + (ax^2 + 1)x + a`
Factorize x3 -12x ( x - 4) - 64
Factorize a3 x3 - 3a2bx2 + 3ab2 x - b3
The value of \[\frac{(0 . 013 )^3 + (0 . 007 )^3}{(0 . 013 )^2 - 0 . 013 \times 0 . 007 + (0 . 007 )^2}\] is
The factors of x3 − 7x + 6 are
If (x + y)3 − (x − y)3 − 6y(x2 − y2) = ky2, then k =
Divide: 6x3 + 5x2 − 21x + 10 by 3x − 2
Divide: 12a2 + ax - 6x2 by 3a - 2x
Divide: m3 − 4m2 + m + 6 by m2 − m − 2
Write in the form of an algebraic expression:
Perimeter (P) of a square is four times its side.
