Advertisements
Advertisements
प्रश्न
Factorize a2 + 4b2 - 4ab - 4c2
Advertisements
उत्तर
On rearranging
= a2 - 4ab + 4b2 - 4c2
= (a)2 - 2 x a x 2b + (2b)2 - 4c2
Using identity a2 - 2ab + b2 = (a - b)2
= (a - 2b)2 - 4c2
= (a - 2b)2 - (2c)2
Using identity a2 - b2 = (a + b)(a - b)
= (a - 2b + 2c)(a - 2b - 2c)
∴ a2 + 4b2 - 4ab - 4c2 = (a - 2b + 2c)(a - 2b - 2c)
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Product of numbers y and z subtracted from 10.
Factorize : x2 + y - xy - x
Factorize the following expressions
8x3 y3 + 27a3
Factorize the following expressions:
x4y4 - xy
Factorize the following expressions:
x3 + 6x2 +12x +16
Find the value of the following expression: 64x2 + 81y2 + 144xy, when x = 11 and \[y = \frac{4}{3}\]
The factors of 8a3 + b3 − 6ab + 1 are
Evaluate:
(i) (a + b)(a - b)
(ii) (a2 + b2)(a + b)(a - b); using the result of (i).
(iii) (a4 + b4)(a2 + b2)(a + b)(a - b); using the result of (ii).
Divide: 25x2y by - 5y2
Express the following properties with variables x, y and z.
Commutative property of multiplication
