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प्रश्न
Factorize a3 x3 - 3a2bx2 + 3ab2 x - b3
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उत्तर
= (ax)3 - 3(ax)2 × b + 3(ax)b2 - b3
= (ax - b)3 [∵ a2 - 3a2b + 3ab2 - b3 = (a - b)3 ]
= (ax - b)(ax - b)(ax - b)
∴ a3 x3 - 3a2bx2 + 3ab2 x - b3 = (ax - b)(ax - b)(ax - b)
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