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प्रश्न
Evaluate: (4x2 - 4x + 1)(2x3 - 3x2 + 2)
योग
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उत्तर
(4x2 - 4x + 1)(2x3 - 3x2 + 2)
= 4x2 (2x3 - 3x2 + 2) - 4x (2x3 - 3x2 + 2) + 1 (2x3 - 3x2 + 2)
= 8x5 - 12x4 + 8x2 - 8x4 + 12x3 - 8x + 2x3 - 3x2 + 2
= 8x5 - 12x4 - 8x4 + 12x3 + 2x3 + 8x2 - 3x2 - 8x + 2
= 8x5 - 20x4 + 14x3 + 5x2 - 8x + 2
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