Advertisements
Advertisements
प्रश्न
Evaluate: (3x - 1)(4x3 - 2x2 + 6x - 3)
Advertisements
उत्तर
(3x - 1)(4x3 - 2x2 + 6x - 3)
= 3x (4x3 - 2x2 + 6x - 3) - 1 (4x3 - 2x2 + 6x - 3)
= 12x4 - 6x3 + 18x2 - 9x - 4x3 + 2x2 - 6x + 3
= 12x4 - 6x3 - 4x3 + 18x2 + 2x2 - 9x - 6x + 3
= 12x4 - 10x3 + 20x2 - 15x + 3
APPEARS IN
संबंधित प्रश्न
Factorize x3 + 8y3 + 6x2 y +12xy2
Factorize a3 x3 - 3a2bx2 + 3ab2 x - b3
If a + b + c = 9 and ab + bc + ca = 40, find a2 + b2 +c2.
(x + y)3 − (x − y)3 can be factorized as
Separate monomials, binomials, trinomials and polynomials from the following algebraic expressions :
8 − 3x, xy2, 3y2 − 5y + 8, 9x − 3x2 + 15x3 − 7,
3x × 5y, 3x ÷ 5y, 2y ÷ 7 + 3x − 7 and 4 − ax2 + bx + y
Multiply: (2x + 3y)(2x - 3y)
Divide: 8m - 16 by - 8
Divide: m2 − 2mn + n2 by m − n
Divide: m3 − 4m2 + m + 6 by m2 − m − 2
Express the following as an algebraic expression:
The product of 12, x, y and z minus the product of 5, m and n.
